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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    The head lights of a jeep are 1.2 m apart. If the pupil of the eye of an observer has a diameter of mm and light of wavelength 5896 \[{{A}^{o}}\]is used, what should be the maximum distance of the jeep from the observer if the two head lights are just separated?

    A)  33.9 km                              

    B)  33.9 m

    C)  3.34 m                                 

    D)  3.39 m

    Correct Answer: C

    Solution :

    Distance of jeep, \[x=\frac{D\times d}{1.22\times \lambda }\] where D = diameter of lens,                 d = seperation between sources. \[\Rightarrow \]               \[x=\frac{(2\times {{10}^{-3}})\times 1.2}{1.22\times 5896\times {{10}^{-10}}}\]                 = 3336 m \[\Rightarrow \]               \[x=3.34\text{ }km\]


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