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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    A shell of mass 20 kg at rest explodes into two fragments whose masses are in the ratio \[2:3\]. The smaller fragment moves with a velocity of\[6\,\,m{{s}^{-1}}\]. The kinetic energy of the larger fragment is

    A)  96 J                                       

    B)  216 J

    C)  144 J                                    

    D)  360 J

    Correct Answer: A

    Solution :

    Total mass of the shell = 20 kg Ratio of the masses of the fragments \[=2:3\] \[\therefore \] Masses of the fragments are 8 kg and 12 kg Now, according to the conservation of momentum                 \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] \[\therefore \]  \[8\times 6=12\times v\] v (velocity of the larger fragment) = 4 m/ s Kinetic energy \[=\frac{1}{2}\,m{{v}^{2}}\]                 \[=\frac{1}{2}\times 12\times {{(4)}^{2}}=96\,J\]


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