A) 4
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
The structure of 2, 3, 4-trichloro pentane is \[H-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ |* \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ |* \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-H\] Hence, two chiral carbon atoms are present in 2, 3, 4-trichloropentane.
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