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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    When cone. \[{{H}_{2}}S{{O}_{4}}\] is heated with \[{{P}_{2}}{{O}_{5}}\] the acid is converted into

    A)  sulphur trioxide

    B)  sulphur dioxide

    C)  sulphur

    D)  a mixture of sulphur dioxide and sulphur trioxide

    Correct Answer: A

    Solution :

    When cone. \[{{H}_{2}}S{{O}_{4}}\] is heated with \[{{P}_{2}}{{O}_{5}}\] the acid is converted into sulphur trioxide. \[2{{H}_{2}}S{{O}_{4}}+2{{P}_{2}}{{O}_{5}}\xrightarrow{{}}\underset{sulphur\text{ }trioxide}{\mathop{2S{{O}_{3}}}}\,+4HP{{O}_{3}}\]


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