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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    The order and degree of the differential equation \[{{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{5}} \right]}^{\frac{1}{3}}}=\frac{{{d}^{2}}y}{d{{x}^{2}}}\] are respectively

    A)  \[1,5\]                                 

    B)  \[2,1\]

    C)  \[2,5\]                                 

    D)  \[2,3\]

    Correct Answer: D

    Solution :

    Given differential equation is \[{{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{5}} \right]}^{1/3}}=\frac{{{d}^{2}}y}{d{{x}^{2}}}\] On cubing both sides, we get                 \[1+{{\left( \frac{dy}{dx} \right)}^{5}}={{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{3}}\] Now, order is 2 and degree is 3.


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