CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    If y is the ratio of specific heats and R is the universal gas constant, then the molar specific heat at constant volume C­ is given by

    A)  \[\gamma R\]                                  

    B)  \[\frac{(\gamma -1)R}{\gamma }\]

    C)  \[\frac{R}{\gamma -1}\]                              

    D)  \[\frac{\gamma R}{\gamma -1}\]

    Correct Answer: C

    Solution :

    From the Mayer?s formula                 \[{{C}_{P}}-{{C}_{V}}=R\]                                             ... (i) and                        \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}\] \[\Rightarrow \]               \[\gamma {{C}_{V}}={{C}_{P}}\]                                                ... (ii) Substituting Eq. (ii) in Eq. (i), we get                 \[\gamma {{C}_{V}}-{{V}_{V}}=R\]                 \[{{C}_{V}}(\gamma -1)=R\]                                 \[{{C}_{V}}=\frac{R}{\gamma -1}\]


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