A) \[3{{p}_{1}}{{V}_{1}}\]
B) \[-3{{p}_{1}}{{V}_{1}}\]
C) \[6{{p}_{1}}{{V}_{1}}\]
D) Zero
Correct Answer: B
Solution :
The net work done in the whole cycle is \[=\frac{1}{2}\times (3{{p}_{1}})\times (2{{V}_{1}})=3{{p}_{1}}{{V}_{1}}\] If the cycle is anticlockwise work done is negative \[\therefore \] \[{{W}_{cycle}}=-3{{p}_{1}}{{V}_{1}}\]
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