A) \[{{75}^{o}}C\]
B) \[{{67}^{o}}C\]
C) \[{{25}^{o}}C\]
D) \[{{33}^{o}}C\]
Correct Answer: A
Solution :
Temperature of interface \[\theta =\frac{{{K}_{1}}{{\theta }_{1}}{{l}_{2}}+{{K}_{2}}{{\theta }_{2}}{{l}_{1}}}{{{K}_{1}}{{l}_{2}}+{{K}_{2}}{{l}_{1}}}\] It is given that \[{{K}_{Cu}}=9{{K}_{s}}\]. So, if \[{{K}_{s}}={{K}_{1}}=K\], then \[{{K}_{Cu}}={{K}_{2}}=9K\] \[\Rightarrow \] \[\theta =\frac{9K\times 100\times 6+K\times 0\times 18}{9K\times 6+K\times 18}\] \[=\frac{5400\,K}{72\,K}={{75}^{o}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
