A) position isomers
B) chain isomers
C) functional isomers
D) optical isomers
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} Methoxy\text{ }methane \\ (alcohol) \end{smallmatrix}}{\mathop{C{{H}_{3}}OC{{H}_{3}},}}\,\] \[\underset{\begin{smallmatrix} Ethanol\text{ }\,\,\text{(}ether) \\ functional\text{ }group \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\] \[({{C}_{2}}{{H}_{6}}O)\] \[({{C}_{2}}{{H}_{6}}O)\] molecular formula In methoxy methane and ethanol both molecular formula is same but functional groups are different, so they are functional isomers.
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