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  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    The centroid of the triangle ABC, where \[A\equiv (2,3),\]\[B\equiv (8,10)\] and \[C\equiv (5,5)\]is

    A)  \[(5,6)\]                             

    B)  \[(6,5)\]

    C)  \[(6,6)\]                             

    D)  \[(15,18)\]

    Correct Answer: A

    Solution :

    Since, the vertices of the triangle are \[A\equiv (2,3),B\equiv (8,10)\]and \[C\equiv (5,5)\]. \[\therefore \]The centroid of \[\Delta ABC=\left( \frac{2+8+5}{3},\frac{3+10+5}{3} \right)=(5,6)\]


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