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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    The magnetic moment of a transition metal ion is \[\sqrt{15}\,BM\]. Therefore, the number of unpaired electrons present in it, is

    A)  3                                            

    B)  4

    C)  1                                            

    D)  2

    Correct Answer: A

    Solution :

    \[\mu =\sqrt{n(n+2)}\] \[\Rightarrow \]                               \[\sqrt{15}=\sqrt{n(n+2)}\] \[\therefore \]                  \[n=3\]


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