CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    A uniform wire of length L, diameter D and density \[\rho \] is stretched under a tension T. The correct relation between, its fundamental frequency \[f\], the length L and the diameter D is

    A) \[f\propto \frac{1}{LD}\]                             

    B) \[f\propto \frac{1}{L\sqrt{D}}\]

    C) \[f\propto \frac{1}{{{D}^{2}}}\]                

    D) \[f\propto \frac{1}{L{{D}^{2}}}\]

    Correct Answer: A

    Solution :

    The fundamental frequency is \[f=\frac{1}{2L}\sqrt{\frac{T}{\mu }}\]                 \[f=\frac{1}{2L}\sqrt{\frac{T}{\rho \pi \frac{{{D}^{2}}}{4}}}=\frac{1}{LD}\sqrt{\frac{T}{\pi \rho }}\]                                                 \[f\propto \frac{1}{LD}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner