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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    The line joining \[A(2,-7)\] and \[B(6,5)\] is divided into 4 equal parts by the points P, Q and R such that\[AQ=RP=QB\]. The mid-point of PR is

    A) \[(4,12)\]                            

    B) \[(-8,1)\]

    C) \[(4,-1)\]                             

    D) \[(8,-2)\]

    Correct Answer: C

    Solution :

    Given that Daygram                 \[AP=PQ=QR=RB\] and        \[AQ=RP=QB\] Since, \[AQ=QB,\] that means Q is the mid point of \[AB=\left[ \frac{2+6}{2},\frac{-7+5}{2} \right]=(4,-1)\] \[\because \] Mid point of \[PR=(4,-1)\]               \[[\because \,\,PQ=QR]\]


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