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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    Wavelength of given light waves in air and in a medium are \[6000\overset{o}{\mathop{A}}\,\]and \[4000\overset{o}{\mathop{A}}\,\] respectively. The critical angle is

    A)  \[{{\tan }^{-1}}\left( \frac{2}{3} \right)\]                              

    B)  \[{{\tan }^{-1}}\left( \frac{3}{2} \right)\]

    C)  \[{{\tan }^{-1}}\left( \frac{2}{3} \right)\]                              

    D)  \[{{\sin }^{-1}}\left( \frac{3}{2} \right)\]

    Correct Answer: C

    Solution :

                    \[\frac{1}{\sin C}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\]                 \[\frac{1}{\sin C}=\frac{6000}{3000}\]                 \[\frac{1}{\sin C}=\frac{6}{2}=\frac{3}{2}\]                 \[\sin C=\frac{2}{3}\]                 \[C={{\sin }^{-1}}\left( \frac{2}{3} \right)\]


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