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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    Two thin lenses have a combined power of +9 D. When they are separated by a distance of 20 cm, their equivalent power becomes +\[+\frac{27}{5}D\]. Their individual powers (in dioptre) are

    A)  1, 8                                       

    B)  2, 7

    C)  3, 6                                       

    D)  4, 5

    Correct Answer: C

    Solution :

    Given,                                 \[{{P}_{1}}+{{P}_{2}}=9\]                 \[P={{P}_{1}}+{{P}_{2}}-d{{P}_{1}}{{P}_{2}}\]                 \[=\frac{27}{5}=9-\frac{20}{100}\times {{P}_{1}}{{P}_{2}}\] Hence, the above equation is correct for                 \[{{P}_{1}}=3\] and \[{{P}_{2}}=6\]


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