A) \[{{T}_{{{H}_{2}}}}=\sqrt{7}\,{{T}_{{{N}_{2}}}}\]
B) \[{{T}_{{{N}_{2}}}}=\,{{T}_{{{H}_{2}}}}\]
C) \[{{T}_{{{N}_{2}}}}=\sqrt{7}{{T}_{{{H}_{2}}}}\]
D) \[{{T}_{{{N}_{2}}}}=2{{T}_{{{H}_{2}}}}\]
Correct Answer: D
Solution :
\[\frac{{{C}_{{{H}_{2}}}}}{{{C}_{{{N}_{2}}}}}=\sqrt{7}=\sqrt{\frac{{{T}_{{{H}_{2}}}}\times 28}{2\times {{T}_{{{N}_{2}}}}}}\] \[7=\frac{14{{T}_{{{H}_{2}}}}}{{{T}_{{{N}_{2}}}}}\] or \[{{T}_{{{N}_{2}}}}=2\,{{T}_{{{H}_{2}}}}\]
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