CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    If \[m\]and \[n\] are degree and order of \[{{(1+y_{1}^{2})}^{2/3}}={{y}_{2}},\]then the value of \[\frac{m+n}{m-n}\]is

    A)  3                                            

    B)  4

    C)  5                                            

    D)  2

    Correct Answer: C

    Solution :

    Given differential equation is \[{{\left( 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right)}^{2/3}}=\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)\]                 \[\Rightarrow \] \[{{\left( 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right)}^{2}}={{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{3}}\] Now,         Order = n = 2 Degree = \[m=3\] Then,      \[\frac{m+n}{m-n}=\frac{3+2}{3-2}=5\]


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