A) 1 : 3 : 5
B) 1 : 2 : 3
C) 1: 4: 9
D) 1: 5 : 6
Correct Answer: A
Solution :
Distance covered in \[{{n}^{th}}\sec \]. \[{{s}_{n}}=u+\frac{a}{2}(2n-1)\] \[\because \] \[u=0\] So, \[{{s}_{n}}=\frac{a}{2}(2n-1),\] a is constant Therefore, \[{{s}_{1}}:{{s}_{2}}:{{s}_{3}}=\{2(1)-1\}:\{2(2)-1\}:\{2(3)-1\}\] \[=1:3:5\]
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