2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of \[60{}^\circ \] with the horizontal. The change in momentum (in magnitude) of the body is

    A)  24.5 N-s                              

    B)  49.0 N-s

    C)  98.0 N-s                              

    D)  50.0 N-s

    Correct Answer: A

    Solution :

    Initial momentum \[=mu=0\] Final momentum = m (Horizontal component of velocity)                                                 \[=m(v\,\,\cos \theta )\]                                                 \[=0.5\times 98\times \cos \,\,60\]                                                 \[=24.5N\text{-s}\] \[\therefore \] Change in momentum \[=24.5-0\]                                                 \[=24.5N\text{-s}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner