Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    The distance travelled by light in glass (refractive index = 1.5) in a nanosecond will be

    A)  45cm                                   

    B)  40cm

    C)  30cm                                   

    D)  20cm

    Correct Answer: D

    Solution :

    Speed of light in glass \[v=\frac{c}{\mu }\] So, distance travelled \[d={{c}_{g}}.t\]                 \[=\frac{c}{\mu }.t\]                 \[=\frac{3\times {{10}^{8}}}{1.5}\times 1\times {{10}^{-9}}\]                 \[=0.2m\]                 \[=20cm\]


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