Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    Light of frequency \[4{{v}_{0}}\] is incident on the metal of the threshold frequency \[{{v}_{0}}.\] The maximum kinetic energy of the emitted photoelectrons is

    A)  \[3h{{v}_{0}}\]                                

    B) \[2h{{v}_{0}}\]

    C)  \[\frac{3}{2}h{{v}_{0}}\]                              

    D) \[\frac{1}{2}h{{v}_{0}}\]

    Correct Answer: A

    Solution :

    Kinetic energy \[\frac{1}{2}m{{v}^{2}}=h(v-{{v}_{0}})\]                 \[=h(4{{v}_{0}}-{{v}_{0}})\]                 \[=3h\,{{v}_{0}}\]


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