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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    At a certain place the horizontal component of the earth's magnetic field is \[{{B}_{0}}\] and the angle of dip is \[45{}^\circ \]. The total intensity of the field at that place will be

    A)  \[{{B}_{0}}\]                                     

    B)  \[\sqrt{2}{{B}_{0}}\]

    C)  \[2B_{0}^{{}}\]                                

    D)  \[B_{0}^{2}\]

    Correct Answer: B

    Solution :

    \[{{B}_{0}}=\,B\,\,\cos \,\theta \] or            \[B=\frac{{{B}_{0}}}{\cos \,\theta }=\frac{{{B}_{0}}}{\cos \,{{45}^{o}}}=\sqrt{2}{{B}_{0}}\]


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