Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    A long sol enoid has n turns per metre and current \[I\] ampere is flowing through it. The magnetic field at the ends of solenoid is

    A)  \[\frac{{{\mu }_{0}}nI}{2}\]                                       

    B)  \[{{\mu }_{0}}nI\]

    C)  zero                                     

    D) \[2{{\mu }_{0}}nI\]

    Correct Answer: A

    Solution :

    Intensity of magnetic field at the ends of a solenoid \[B=\frac{{{\mu }_{0}}nI}{2}\] Intensity of magnetic field at the centre of solenoid \[B={{\mu }_{0}}nI\]                 \[{{B}_{centre}}=2{{B}_{end}}\]


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