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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    A circular coil of 500 turns of wire has an enclosed area of 0.1 m2 per turn. It is kept perpendicular to a magnetic field of induction 0.2 T and rotated by \[180{}^\circ \] about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of son?

    A)  0.2 C                                    

    B)  0.4 C

    C)  2 C                                        

    D)  4 C

    Correct Answer: B

    Solution :

    According to Faraday's second law of electromagnetic induction emf \[e=-\frac{d\phi }{dt}\]                 or            \[IR=\frac{-d\phi }{dt}\] or \[Idt=-\frac{d\phi }{R}\]                 \[\because \]     \[Idt=q\]                 \[\therefore \]  \[q=-\frac{d\phi }{R}\]                 \[\because \]     \[d\phi =\frac{NBA(\cos \,{{\theta }_{2}}-\cos {{\theta }_{1}})}{R}\] Given,   \[N=500,\] \[R=50\Omega ,\] \[A=0.1{{m}^{2}}\] \[\therefore \] \[q=\frac{500\times (0.2)\times (0.1)\times (\cos \,{{180}^{o}}-\cos {{0}^{o}})}{50}\] \[\Rightarrow \]               \[q=0.4C\]


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