A) 10 A
B) 20 A
C) 14.14 A
D) 7.07 A
Correct Answer: C
Solution :
Peak value of current \[{{I}_{0}}=\sqrt{2}{{I}_{\max }}\] or \[{{I}_{0}}=\sqrt{2}\times 10A\] \[\Rightarrow \] \[{{I}_{0}}=14.14A\]
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