A) \[BaC{{l}_{2}}>NaCl>glucose\]
B) \[NaCl>BaC{{l}_{2}}>glucose\]
C) \[glucose>BaC{{l}_{2}}>NaCl\]
D) \[glucose>NaCl>BaC{{l}_{2}}\]
Correct Answer: A
Solution :
Glucose is an organic compound and this is not ionised while \[BaC{{l}_{2}}\] and \[NaCl\] are inorganic compounds and they are strong electrolytes and are normally 100% ionised at normal dilution. \[BaC{{l}_{2}}\rightleftharpoons B{{a}^{2+}}+2C{{l}^{-}}\] \[NaCl\rightleftharpoons N{{a}^{+}}+C{{l}^{-}}\] \[\because \]Osmotic pressure is a colligative property and hence, depends on the number of ions. So, decreasing order of osmotic pressure is\[BaC{{l}_{2}}>NaCl>\]glucose
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