A) \[-{{1.86}^{o}}C\]
B) \[-{{0.93}^{o}}C\]
C) \[-{{0.093}^{o}}C~\]
D) \[{{0.93}^{o}}C\]
Correct Answer: C
Solution :
Molal depression constant \[{{k}_{f}}={{1.86}^{o}}C\] Molality \[=0.05\] \[\Rightarrow \] \[\Delta {{T}_{f}}={{k}_{f}}\times molality\] \[\Delta {{T}_{f}}=1.86\times 0.05\] \[\Delta {{T}_{f}}={{0.093}^{o}}C\] \[\Delta {{T}_{f}}={{T}_{1}}-{{T}_{2}}\] where, \[{{T}_{1}}\] = freezing point of solvent \[{{T}_{2}}\]= freezing point of solution \[{{T}_{1}}={{0}^{o}}C\] \[0.093=0-{{T}_{2}}\] \[{{T}_{2}}=-0.093\]
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