A) amonium nitrate
B) \[N{{O}_{2}}\]
C) \[NO\]
D) \[~{{N}_{2}}O\]
Correct Answer: A
Solution :
\[Zn\] reacts with very dilute \[HN{{O}_{3}}\]\[(6%)\] to form \[N{{H}_{4}}N{{O}_{3}}\]and \[Zn{{(N{{O}_{3}})}_{2}}\]. \[4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\]\[+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
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