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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    The temperature of two bodies A and B are respectively \[727{}^\circ C\] and \[327{}^\circ C\]. The ratio of rates of heat radiated by them is

    A)  727:327                               

    B)  5 : 3

    C)  25 : 9                                    

    D)  625 : 81

    Correct Answer: D

    Solution :

    According to Stefan's law, rate of heat radiated \[E\propto {{T}^{4}}\]                 \[\therefore \] \[\frac{{{E}_{A}}}{{{E}_{B}}}={{\left( \frac{727+273}{327+273} \right)}^{4}}={{\left( \frac{1000}{600} \right)}^{4}}=\frac{625}{81}\]                 So,          \[{{E}_{A}}:{{E}_{B}}=625:81\]


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