2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    An emf of 100 mV is induced in a coil when the current in another nearby coil becomes 10 A from zero in 0.1 s. The coefficient of mutual induction between the two coils will be

    A)  1mH                                     

    B)  10 mH

    C)  100 mH                               

    D)  1000 mH

    Correct Answer: A

    Solution :

    Given,  \[e=100mV=100\times {{10}^{-3}}V\] \[dI=10-0=10A,\] \[dt=0.1s\] So, coefficient of mutual inductance                 \[M=\frac{e}{dI/dt}=\frac{100\times {{10}^{-3}}}{10/0.1}\]                 \[={{10}^{-3}}H=1mH\]


You need to login to perform this action.
You will be redirected in 3 sec spinner