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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    \[50\text{ }mL\]\[10\text{ }N\] \[{{H}_{2}}S{{O}_{4}},\]\[25\text{ }mL\]\[12N\] \[HCl\]and \[40\text{ }mL\]\[5N\]\[HN{{O}_{3}}\] were mixed together and the volume of the mixture was made \[1000\text{ }mL\]by adding water. The normality of the resultant solution will be

    A)  \[1\text{ }N\]                                  

    B)  \[\text{2 }N\]

    C)  \[\text{3 }N\]                                  

    D)  \[\text{4 }N\]

    Correct Answer: A

    Solution :

    Milli equivalents of \[{{H}_{2}}S{{O}_{4}}=N\times V=10\times 50=500\] Milli equivalents of \[HCl\] \[=N\times V=12\times 25=300\] Milli equivalents of \[HN{{O}_{3}}\]                 \[=N\times V=5\times 40=200\] Total milli equivalents                 \[=500+300+200=1000\] Total volume \[=1000\text{ }mL\] Milli equivalents \[=N\times V\]                                 \[1000=N\times 1000\]                                 \[N=\frac{1000}{1000}=1N\]


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