A) Ammonium nitrate
B) \[N{{O}_{2}}\]
C) \[NO\]
D) \[{{N}_{2}}O\]
Correct Answer: A
Solution :
\[Zn\]react with very dil. \[HN{{O}_{3}}\] and form zinc nitrate \[Zn(N{{O}_{3}}){{ & }_{2}},\]\[N{{H}_{4}}N{{O}_{3}}\] and\[{{H}_{2}}O\]. \[4Zn+10HN{{O}_{3}}\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}\]\[+N{{H}_{4}}N{{O}_{3}}+{{H}_{2}}O\]
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