A) \[M\]
B) \[M/2\]
C) \[M/5\]
D) \[M/4\]
Correct Answer: C
Solution :
\[\overset{+7}{\mathop{2KMn{{O}_{4}}}}\,+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+\overset{+2}{\mathop{2MnS{{O}_{4}}}}\,\]\[+3{{H}_{2}}O+5O\] Decrease in O.N per \[Mn\] atom \[=5\] Suppose molecular weight of \[KMn{{O}_{4}}=M\] \[Eq.\,mass=\frac{\begin{array}{*{35}{l}} molecular\text{ }weight\text{ }of\text{ }oxidant \\ ~~~~~~~~~~~~\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,or\text{ }reductant \\ \end{array}}{change\text{ }in\text{ }oxidation\text{ }number\text{ }\times n}\]M Eq. mass \[=\frac{M}{5\times 1}\] Eq. mass \[\frac{M}{5}\]
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