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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    If the acceleration-displacement graph of simple harmonic motion of a particle is given, then the time period of the particle will be

    A)  2n                                         

    B)  3n

    C)  An                                        

    D)  5n

    Correct Answer: A

    Solution :

    Slope of acceleration-displacement graph \[=-{{\omega }^{2}}\] \[\therefore \]  \[{{\omega }^{2}}=\tan \,{{45}^{o}}=1\] \[\therefore \]  \[\omega =1\] But             \[\omega =\frac{2\pi }{T}=1\] \[\therefore \]  \[T=2\pi \]


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