Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    If the escape velocity for a monkey from the earth surface is 11.2 km/s, then the escape velocity for the elephant is

    A)  less than 11.2                   

    B)  more than 11.2

    C)  11.2 km/s                          

    D)  None of these

    Correct Answer: C

    Solution :

    Escape velocity \[{{v}_{e}}=\sqrt{2g{{R}_{e}}}=\sqrt{\frac{2GM}{{{R}_{e}}}}\]where g = acceleration due to gravity, \[{{R}_{e}}=\] = radius of the earth, G = gravitational constant and M = mass of the earth. Therefore, escape velocity do not depend on the mass of the object to be escaped. Hence, escape velocity for the elephant is also\[11.2\text{ }km/s\].


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