2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    The electric field between two parallel plates of a capacitor is \[2.1\times {{10}^{-5}}.\] If a medium is inserted between the plates than the electric field becomes \[1.0\times {{10}^{-5}}.\] Now, the value of dielectric will be

    A)  2                                            

    B)  3

    C)  4                                            

    D)  5

    Correct Answer: A

    Solution :

    \[E=\frac{\sigma }{{{\varepsilon }_{0}}}=2.1\times {{10}^{-5}}\] \[E'=\frac{\sigma }{{{\varepsilon }_{0}}K}=1\times {{10}^{-5}}\] \[\therefore \]  \[\frac{E}{E'}=\frac{\sigma }{{{\varepsilon }_{0}}}\times \frac{{{\varepsilon }_{0}}K}{\sigma }=\frac{2.1\times {{10}^{-5}}}{1\times {{10}^{-5}}}\] or            \[K=2.1\approx 2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner