question_answer

If \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{i}}\] is the inversion temperature, \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{n}}\] is the neutral temperature, \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{c}}\] is the temperature of the cold junction for thermocouple, then

A)  \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{i}}+{{\text{ }\!\!\theta\!\!\text{ }}_{c}}={{\text{ }\!\!\theta\!\!\text{ }}_{n}}\]                       

B) \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{i}}\text{-}{{\text{ }\!\!\theta\!\!\text{ }}_{c}}=2{{\text{ }\!\!\theta\!\!\text{ }}_{n}}\]

C) \[\,\frac{{{\text{ }\!\!\theta\!\!\text{ }}_{i}}\text{+}\,{{\text{ }\!\!\theta\!\!\text{ }}_{c}}}{2}={{\text{ }\!\!\theta\!\!\text{ }}_{n}}\]                                   

D) \[\,{{\text{ }\!\!\theta\!\!\text{ }}_{c}}\text{-}{{\text{ }\!\!\theta\!\!\text{ }}_{i}}=2{{\text{ }\!\!\theta\!\!\text{ }}_{n}}\]

Correct Answer: C

Solution :

\[{{\theta }_{n}}-{{\theta }_{c}}={{\theta }_{i}}-{{\theta }_{n}}\] or            \[{{\theta }_{n}}=\frac{{{\theta }_{i}}+{{\theta }_{c}}}{2}\]