Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    Each resistance shown in the circuit is of \[10\,\Omega .\] The equivalent resistance between the points X and V is

    A)  \[10\,\Omega \]                             

    B)  \[20\,\Omega \]

    C)  \[25\,\Omega \]                             

    D)  \[30\,\Omega \]

    Correct Answer: A

    Solution :

    In arm ABC, resultant resistance \[R'={{R}_{1}}+{{R}_{2}}=10+10=20\Omega \] In arm ADC resultant resistance                 \[R'\,'={{R}_{3}}+{{R}_{4}}=10+10=20\Omega \] Resistances \[R'\] and \[R'\,'\] are in parallel, \[\therefore \]  \[\frac{1}{R}=\frac{1}{R'}+\frac{1}{R'\,'}=\frac{1}{20}+\frac{1}{20}\]                 \[R=10\Omega \]


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