A) \[CH{{I}_{3}}\]and \[HCOOK\]
B) \[CH{{I}_{3}}\] and \[C{{H}_{3}}COOK\]
C) \[C{{H}_{4}}\]and \[HCOOK\]
D) \[CH{{I}_{3}}\] and \[{{H}_{2}}\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}OH+4{{I}_{2}}+6NaOH\xrightarrow{{}}\underset{Iodofrom}{\mathop{CH{{I}_{3}}}}\,\] \[+HCOONa+5NaI+5{{H}_{2}}O\] \[CH{{I}_{3}}+3KOH\xrightarrow{{}}\left[ H-\underset{OH}{\mathop{\underset{|}{\mathop{\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-OH \right]\xrightarrow{-{{H}_{2}}O}\] \[H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH\] \[H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+KOH\xrightarrow{{}}H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OK+{{H}_{2}}O.\]
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