A) 3
B) 2
C) 1
D) 0
Correct Answer: A
Solution :
The molecular configuration of \[{{N}_{2}}\] is \[\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}}\sigma 2{{s}^{2}}\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\left\{ \begin{matrix} \pi 2{{p}_{y}}^{2} \\ \pi 2{{p}_{x}}^{2} \\ \end{matrix}\sigma 2{{p}_{z}}^{2} \right.\] \[\left\{ \begin{matrix} \overset{*}{\mathop{\pi }}\,2{{p}_{y}} \\ \overset{*}{\mathop{\pi }}\,2{{p}_{x}} \\ \end{matrix}\overset{*}{\mathop{\sigma }}\,2{{p}_{z}} \right.\] number of bonding electrons \[Bond\text{ }order=\frac{-\text{ }number\text{ }of\text{ }antibonding\text{ }electrons}{2}\] \[=\frac{10-4}{2}\] \[\therefore \] Bond order = 3
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