A) \[k=\frac{2.303}{t}{{\log }_{10}}\frac{a}{a-x}\]
B) \[k=\frac{1}{t}\frac{x}{a[a-x]}\]
C) \[k=\frac{1}{t}\frac{x}{{{a}^{2}}{{[a-x]}^{2}}}\]
D) None of the above
Correct Answer: B
Solution :
Expression for velocity constant for the second order reaction is \[k=\frac{1}{t}.\frac{x}{a(a-x)}\]
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