2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    Two large closely spaced concentric spheres (both are black body radiators) are maintained at temperature of 200 K and 300 K respectively. The space between them is evacuated. The net rate of energy transfer between the two spheres will be (\[\sigma \]\[=5.672\times {{10}^{8}}MKS\] unit)

    A)  368.68W/m2                     

    B)  3686.8 W/m2

    C)  36.868 W/m2                    

    D)  36868 W/m2

    Correct Answer: A

    Solution :

    Net rate of energy transfer \[(E)=\sigma T_{1}^{4}-\sigma T_{2}^{4}\] \[=\sigma (T_{1}^{4}-T_{2}^{4})\]                 \[=5.672\times {{10}^{-8}}[{{(300)}^{4}}-{{(200)}^{4}}]\]                 \[=5.672\times {{10}^{-8}}\times (81-16)\times {{10}^{8}}\]                 \[=368.68W/{{m}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner