A) \[4.4\times {{10}^{-19}}\text{J}\]
B) \[2.5\times {{10}^{-19}}\text{J}\]
C) \[1.25\times {{10}^{-17}}\text{J}\]
D) \[2.5\times {{10}^{-17}}\text{J}\]
Correct Answer: A
Solution :
Given, \[\lambda =450mm=4.5\times {{10}^{-7}}m\] Energy of photon \[(E)=\frac{hc}{\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.5\times {{10}^{-7}}}\] \[=4.4\times {{10}^{-19}}J\]
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