Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    Two opposite and equal charges of \[4\times {{10}^{-8}}C\] when placed \[2\times {{10}^{-2}}cm\] away form a dipole. If this dipole is placed in an external electric field \[4\times {{10}^{8}}N/C,\] the value of maximum torque and the work done in rotating it through \[180{}^\circ C\] will be

    A)  \[64\times {{10}^{-4}}Nm\text{ }and\text{ }64\times {{10}^{-4}}J\]

    B)  \[32\times {{10}^{-4}}Nm\text{ }and\text{ }32\times {{10}^{-4}}J\]

    C)  \[64\times {{10}^{-4}}Nm\text{ }and\text{ }32\times {{10}^{-4}}J\]

    D)  \[32\times {{10}^{-4}}Nm\text{ }and\text{ }64\times {{10}^{-4}}J\]

    Correct Answer: D

    Solution :

    Given,   \[q=4\times {{10}^{-8}}C,\] \[2a=2\times {{10}^{-2}}cm\] \[=2\times {{10}^{-4}}m\] Electric dipole moment                 \[(p)=q\times 2a=4\times {{10}^{-8}}\times 2\times {{10}^{-4}}\]                 \[=8\times {{10}^{-12}}\text{C-m}\]                 \[E=4\times {{10}^{8}}N/C\] Torque acting on electric dipole in an electric field                 \[\tau =Ep\,\sin \,\theta \] Maximum torque \[{{\tau }_{\max }}=Ep\]                                 \[=4\times {{10}^{8}}\times 8\times {{10}^{-12}}\]                                 \[=32\times {{10}^{-4}}N\text{-m}\] Work done in rotating electric dipole through an angle \[\theta ,\]                                 \[W=Ep(1-\cos \,\theta )\]                                 \[{{W}_{{{180}^{o}}}}=Ep(1-\cos \,{{180}^{o}})=2Ep\]                                 \[=64\times {{10}^{-4}}J\]


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