Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    In Figure, \[a<r<b\] then intensity at r distance from centre is

    A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{3q}{{{r}^{2}}}-\frac{q}{{{(b-r)}^{2}}} \right]\]        

    B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{-q}{{{r}^{2}}} \right]\]

    C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\left( \frac{3q}{{{r}^{2}}} \right)\]                     

    D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{3q}{{{a}^{2}}}\]

    Correct Answer: C

    Solution :

    Electric field inside a charged spherical shell is zero. Therefore, electric field at distance r from the centre is only due to charge 3q distributed over spherical shell of radius a. \[\therefore \]Electric field intensity at distance r from the centre                 \[=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{3q}{{{r}^{2}}}\]


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