2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A power line carrying 10 A current from east to west in earth's magnetic field of 10-T, then force acting on its 1 m length is

    A)  zero                                     

    B)  \[{{10}^{-2}}N\]

    C)  \[{{10}^{-3}}N\]                              

    D)  \[{{10}^{-4}}N\]

    Correct Answer: C

    Solution :

    Given  \[I=10A,\]\[B={{10}^{-4}}T,\] \[l=1m\] Force acting on current carrying wire is                 \[F=BIl\sin \,\theta \]                 \[={{10}^{-4}}\times 10\times 1\times \sin \,{{90}^{o}}\]                 \[={{10}^{-3}}N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner