Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    A copper rod of length; is rotated about one  end perpendicular to the uniform magnetic field B with the constant angular velocity\[\omega .\]The induced emf between the two ends is

    A)  \[B\omega {{l}^{2}}\text{/2}\]                                 

    B)  \[B\omega {{l}^{2}}\]

    C)  \[2B\omega {{l}^{2}}\]                                 

    D)  zero

    Correct Answer: A

    Solution :

    Induced emf between the two ends of the rod \[=\frac{1}{2}B\omega {{l}^{2}}\]


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