A) 2.2 H
B) 0.22 H
C) 1.6 H
D) 0.16 H
Correct Answer: D
Solution :
Given \[V=220volt\] \[f=50\,\,cycles/s\]. \[{{X}_{L}}=50\Omega \] \[{{X}_{L}}=L\omega =L.2\pi f\] \[\therefore \] \[L=\frac{{{X}_{L}}}{2\pi f}=\frac{50}{2\times \frac{22}{7}\times 50}\] \[=\frac{7}{44}=0.16H\]
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