Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    The number of unpaired electrons is maximum in (Atomic no. \[Ti=22,V=23,Cr=24,Fe=26)\])

    A)  \[Fe\]                                  

    B)  \[Cr\]

    C)  \[Ti\]                                   

    D)  \[V\]

    Correct Answer: B

    Solution :

    Electronic configuration of given element is as follows \[_{26}Fe-1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},4{{s}^{2}},3{{d}^{6}}\] \[\therefore \] Number of unpaired electrons = 4 \[_{24}Cr-1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{1}}3{{d}^{5}}\] \[\therefore \]Number of unpaired electrons = 6 \[_{22}Ti-1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{2}},3{{d}^{2}}\] \[\therefore \]Number of unpaired electrons = 2                 \[_{23}V-1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{2}},3{{d}^{3}}\] \[\therefore \]Number of unpaired electrons = 3


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