A) \[{{10}^{4}}\]
B) \[{{10}^{3}}\]
C) \[{{10}^{2}}\]
D) \[1\]
Correct Answer: B
Solution :
Cell constant \[=0.4c{{m}^{-1}}\] Resistance \[=40\text{ }ohm\] \[\therefore \]Conductivity \[=\frac{1}{40}oh{{m}^{-1}}\] Concentration of solution \[=0.01\text{ }M\] Specific conductivity = conductivity x cell Constant \[=\frac{1}{40}oh{{m}^{-1}}\times 0.4c{{m}^{-1}}\] \[\therefore \] Specific conductivity \[=0.01oh{{m}^{-1}}\,c{{m}^{-1}}\] Molar conductivity \[=\frac{specific\text{ }conductivity\times 1000}{concentration\text{ }\left( molarity \right)}\] \[=\frac{0.01\times 1000}{0.01}oh{{m}^{-1}}\,\,c{{m}^{2}}\,mo{{l}^{-1}}\] \[\therefore \] Molar conductivity \[=1000\text{ }oh{{m}^{-1}}\text{ }c{{m}^{2}}\text{ }mo{{l}^{-1}}\]
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